logx-1(2-x-x^2)=0

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Solution for logx-1(2-x-x^2)=0 equation:


Simplifying
logx + -1(2 + -1x + -1x2) = 0
glox + (2 * -1 + -1x * -1 + -1x2 * -1) = 0
glox + (-2 + 1x + 1x2) = 0

Reorder the terms:
-2 + glox + 1x + 1x2 = 0

Solving
-2 + glox + 1x + 1x2 = 0

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + glox + 1x + 2 + 1x2 = 0 + 2

Reorder the terms:
-2 + 2 + glox + 1x + 1x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + glox + 1x + 1x2 = 0 + 2
glox + 1x + 1x2 = 0 + 2

Combine like terms: 0 + 2 = 2
glox + 1x + 1x2 = 2

Add '-1x' to each side of the equation.
glox + 1x + -1x + 1x2 = 2 + -1x

Combine like terms: 1x + -1x = 0
glox + 0 + 1x2 = 2 + -1x
glox + 1x2 = 2 + -1x

Add '-1x2' to each side of the equation.
glox + 1x2 + -1x2 = 2 + -1x + -1x2

Combine like terms: 1x2 + -1x2 = 0
glox + 0 = 2 + -1x + -1x2
glox = 2 + -1x + -1x2

Divide each side by 'lox'.
g = 2l-1o-1x-1 + -1l-1o-1 + -1l-1o-1x

Simplifying
g = 2l-1o-1x-1 + -1l-1o-1 + -1l-1o-1x

Reorder the terms:
g = -1l-1o-1 + 2l-1o-1x-1 + -1l-1o-1x

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